Matematika Sekolah Menengah Atas [+6]
f(x) = 555 + 67 - x² + 10x
f(5) = ?
.
maap pelit poin, blm push :v​

[+6]
f(x) = 555 + 67 - x² + 10x
f(5) = ?
.
maap pelit poin, blm push :v​

f(x) = 555 + 67 - x² + 10x

f(5) = 555 + 67 - 5² + 10(5)

f(5) = 555 + 67 - (5 × 5) + 50

f(5) = 555 + 67 - 25 + 50

f(5) = 622 - 25 + 50

f(5) = 597 + 50

f(5) = 647

[tex] \\ \\ [/tex]

✘ Diketahui:

f(x) = 555 + 67 - x² + 10x

[tex]------[/tex]

✘ Ditanya:

f(5) =

[tex]------[/tex]

✘ Jawab:

f(5) = 555 + 67 - 5² + 10(5)

f(5) = 555 + 67 - (5 × 5) + 10(5)

f(5) = 555 + 67 - (25) + 10(5)

f(5) = 555 + 67 - (25) + 50

f(5) = 622 - (25) + 50

f(5) = 597 + 50

f(5) = 647

[tex]------[/tex]

✘ Jadi, fungsi dari f(5) adalah 647

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